27^2=16x^2

Solution for 27^2=16x^2 equation:

27^2=16x^2

We move all terms to the left:

27^2-(16x^2)=0

We add all the numbers together, and all the variables

-16x^2+729=0

a = -16; b = 0; c = +729;
Δ = b2-4ac
Δ = 02-4·(-16)·729
Δ = 46656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{46656}=216$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-216}{2*-16}=\frac{-216}{-32}
=6+3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+216}{2*-16}=\frac{216}{-32}
=-6+3/4
$